2x^2+20x+57=0

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Solution for 2x^2+20x+57=0 equation:


Simplifying
2x2 + 20x + 57 = 0

Reorder the terms:
57 + 20x + 2x2 = 0

Solving
57 + 20x + 2x2 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
2 the coefficient of the squared term: 

Divide each side by '2'.
28.5 + 10x + x2 = 0

Move the constant term to the right:

Add '-28.5' to each side of the equation.
28.5 + 10x + -28.5 + x2 = 0 + -28.5

Reorder the terms:
28.5 + -28.5 + 10x + x2 = 0 + -28.5

Combine like terms: 28.5 + -28.5 = 0.0
0.0 + 10x + x2 = 0 + -28.5
10x + x2 = 0 + -28.5

Combine like terms: 0 + -28.5 = -28.5
10x + x2 = -28.5

The x term is 10x.  Take half its coefficient (5).
Square it (25) and add it to both sides.

Add '25' to each side of the equation.
10x + 25 + x2 = -28.5 + 25

Reorder the terms:
25 + 10x + x2 = -28.5 + 25

Combine like terms: -28.5 + 25 = -3.5
25 + 10x + x2 = -3.5

Factor a perfect square on the left side:
(x + 5)(x + 5) = -3.5

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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